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x^2+0.00074x-0.0001628=0
a = 1; b = 0.00074; c = -0.0001628;
Δ = b2-4ac
Δ = 0.000742-4·1·(-0.0001628)
Δ = 0.0006517476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.00074)-\sqrt{0.0006517476}}{2*1}=\frac{-0.00074-\sqrt{0.0006517476}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.00074)+\sqrt{0.0006517476}}{2*1}=\frac{-0.00074+\sqrt{0.0006517476}}{2} $
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